3/4x^2+5/2x-18=50

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Solution for 3/4x^2+5/2x-18=50 equation:


x in (-oo:+oo)

(3/4)*x^2+(5/2)*x-18 = 50 // - 50

(3/4)*x^2+(5/2)*x-50-18 = 0

3/4*x^2+5/2*x-68 = 0

DELTA = (5/2)^2-(-68*3/4*4)

DELTA = 841/4

DELTA > 0

x = ((841/4)^(1/2)-5/2)/(3/4*2) or x = (-(841/4)^(1/2)-5/2)/(3/4*2)

x = 8 or x = -34/3

x in { -34/3, 8 }

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